I've just downloaded referencefinder, and it would help to have a topic on it just so that others can have a knowledge base when they start using it.
Please contribute!!
ReferenceFinder Tips and Tricks
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WhisperPuffin
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WhisperPuffin
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N-section of angles emenating from a corner.
replace n with the division you want, and x with the number of these divisions.
This is what you need to enter into your calculator:
tan (90/n*x)
Call this value a. Now, in Referencefinder, click on line, and enter in as follows:
x1:1 y1:a
x2:0 y2:0
Now you have a sequence of diagrams n-secting the bottom left corner!
replace n with the division you want, and x with the number of these divisions.
This is what you need to enter into your calculator:
tan (90/n*x)
Call this value a. Now, in Referencefinder, click on line, and enter in as follows:
x1:1 y1:a
x2:0 y2:0
Now you have a sequence of diagrams n-secting the bottom left corner!
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ftangdude55
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What do you mean by "replace n with the division you want"? Does that mean the calculated angle of the division (ex 90/7=12.857142857142857142857142857143)?WhiperPuffin wrote:replace n with the division you want, and x with the number of these divisions.
This is what you need to enter into your calculator:
tan (90/n*x)
And does the equation mean 90 divided by n multiplied by x?
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origamimasterjared
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Good point WhisperPuffin!
Yes, ftangdude, you would do tan(3*90/7). Remember, you usually don't want to find the 1/n mark, because then finding the others takes even more work. What you want to do is find the n-2, n-4, n-8, n-16, etc. mark. (Or likewise the 2, 4, 8, 16, etc. mark) This number is whatever the largest power of 2 below n is. For instance to divide into 13, find 5/13 or 8/13, to divide into 7 find 3/7 or 4/7. Then you can divide the 2, 4, 8, 16 etc. easily.
Yes, ftangdude, you would do tan(3*90/7). Remember, you usually don't want to find the 1/n mark, because then finding the others takes even more work. What you want to do is find the n-2, n-4, n-8, n-16, etc. mark. (Or likewise the 2, 4, 8, 16, etc. mark) This number is whatever the largest power of 2 below n is. For instance to divide into 13, find 5/13 or 8/13, to divide into 7 find 3/7 or 4/7. Then you can divide the 2, 4, 8, 16 etc. easily.
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ftangdude55
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Oh. thanks Jared. 
Just another question... what does "Tan" mean? I understand what I need to do for the equation, but, oh well. And also, once I multiply 12.8571 by 3, do I make the product (38.5714) into a decimal (0.3857)? It doesn't seem like it to me, because I tried that in Reference Finder, and it didn't work out.
Just another question... what does "Tan" mean? I understand what I need to do for the equation, but, oh well. And also, once I multiply 12.8571 by 3, do I make the product (38.5714) into a decimal (0.3857)? It doesn't seem like it to me, because I tried that in Reference Finder, and it didn't work out.
Last edited by ftangdude55 on May 11th, 2009, 10:15 pm, edited 1 time in total.
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Daydreamer
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ftangdude55
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I'm only in grade 7... I have absolutely no idea how to do trigonometry. 
Would "tan" be the side length of the square?
Would "tan" be the side length of the square?
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Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
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Tan is what you do in Mexico on Spring break!
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ftangdude55
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Haha! 
But seriously, how do I calculate the value "a", with respect to the Tangent?
But seriously, how do I calculate the value "a", with respect to the Tangent?
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Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
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origamimasterjared
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Or at my school all year longqtrollip wrote:Tan is what you do in Mexico on Spring break!
ftangdude, tan means tangent. It's a trigonometric function made by dividing the side of a right triangle opposite of an angle by the side adjacent to that angle (the other short side).
Also if you want to do 3/7 you do 3/7, don't expand it into a decimal.
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ftangdude55
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I am incredibly confused... do you multiply the tangent by the the equation in the brackets (like in a distributive algebraic equation)?
If that is so, then the tangent for a 3/7 right triangle is 0.8100 of a square, and therefore, a=31.2428. But how would I put that value into ReferenceFinder? Any x or y values need to be <1...
If that is so, then the tangent for a 3/7 right triangle is 0.8100 of a square, and therefore, a=31.2428. But how would I put that value into ReferenceFinder? Any x or y values need to be <1...
My Flickr
Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
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origamimasterjared
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No, you don't multiply the tangent. Tangent is a function. You'll learn about it in algebra, don't worry about it. The only pertinent part here is that if you type into your scientific calculator:
3/7 x 90 then hit tan
or if it's one of the nicer ones:
tan(3/7 x 90)
You can plug the resulting number into ReferenceFinder to find the spot you need.
3/7 x 90 then hit tan
or if it's one of the nicer ones:
tan(3/7 x 90)
You can plug the resulting number into ReferenceFinder to find the spot you need.
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ftangdude55
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Oh, I see. Thanks, Jared (I wonder how many times I've written that; you're such a helpful person )
EDIT: Well, I put in the equation, and it totals out to 1.2540. I put that into reference finder, and it didn't work... What should I do to make it work? Do I just use the .2540 as y1?
)EDIT: Well, I put in the equation, and it totals out to 1.2540. I put that into reference finder, and it didn't work... What should I do to make it work? Do I just use the .2540 as y1?
My Flickr
Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
Hi! It's been a long while since I've been active on here. I deleted my Dropbox years ago, so some things, like my Dragonfly Varileg guide, are lost to time. I may still have other things, though! Email me if you have any questions.
It looks like you put in 4/7 instead of 3/7. The problem is, with the specific scenario Jared gave, you need to use an angle less than 45º for it to work. Fortunately we're working on a square, and that's not very hard to do... just measure from the other side. Using 3/7, I got an answer of .7974, which fits into referencefinder much better.
I find that for side and angle divisions, it's simpler to use a Fujimoto approximation. It's just as accurate, and doesn't take a computer to figure out...
I find that for side and angle divisions, it's simpler to use a Fujimoto approximation. It's just as accurate, and doesn't take a computer to figure out...
