Page 1 of 1
Seth Friedman - Hermit Crab (CP)
Posted: May 30th, 2009, 10:29 am
by Cephalopod
Sometimes when I go through pictures on flickr, reference points are written out/ displayed. Thing is, I don't know how to understand them
Here is an example from Seth Friedman's Hermit Crab:
You'll have to do some ref finder work.
(sqrt2+1):4:4:(sqrt2+1)
Help would be greatly appreciated.
I did use the search thing and typed in 'reference point help' and I got 38 pages of results. So I'm sorry if this has already been asked

Posted: May 30th, 2009, 10:40 am
by Ben385
Well, you see those aren't reference points. They show the distribution of paper using cirlce/river packing. Each polygon represents a flap, and the gaps in between spread them out.
Hope that helps!
Posted: May 30th, 2009, 11:35 am
by Wizmatt
Robert Langs' designs use silly reference points too. The only way to find out were they are is to use a calculator and ruler, or download reference finder from his website:
http://www.langorigami.com/science/reff ... inder.php4
As ted385 said above, what's on the cp for the hermit crab demonstates the ammount of paper used for each flap, sometimes they are linear like that, and sometimes they can be circular, hence 'circle packing'.
Hope this helps you out.
Posted: May 30th, 2009, 2:02 pm
by ftangdude55
I also find that the best way to calculate reference points is by using a calculator and a ruler. It's a relatively simple process, but when doing it, it is absolutely necessary to use a centimeter ruler, because inches are divided into 16ths. You need to have base 10 to make the calculations correct.
So basically, all you need to do is first: Measure the side length of the square. Then measure the reference point(s). Once you have found out the distance, divide the distance that you measure by the side length of the square. Now you will have a decimal. Use the first 4 decimal points, and there you have it. A reference point.
Hope that helped.
Posted: May 30th, 2009, 2:29 pm
by origami_8
What you need to find is the point marked in green here:
Afterwards you can make angle bisectors to get the blue diagonals and more angle bisectors to get the remaining lines needed.
To find this point measure the side length of the square and the distance of the point from a side and divide the distance through the length. Then add this number to Reference finder to get a folding sequence.
You can get Reference finder here:
http://langorigami.com/science/reffinder/reffinder.php4
Posted: May 30th, 2009, 3:05 pm
by Ben385
Anna, isn't the majority of this model based of a 26 by 26 grid? I counted, and I'm pretty sure it is.
Posted: May 30th, 2009, 3:51 pm
by Cephalopod
Thanks so much for your help everyone!
So basically, you need to find the green point because that's where everything else, all the other angles, stem from?
Also, what does '(sqrt2+1):4:4:(sqrt2+1)' do? Is that the ratio of paper used? I don't really understand that bit.
Posted: May 30th, 2009, 4:31 pm
by origami_8
(sqrt2+1):4:4:(sqrt2+1) is probably a reference to those four lengths between the green points:
To ted385:
I doubt that the CP is based on a regular grid, but probably it would be a good approximation.
Posted: May 30th, 2009, 8:52 pm
by origamimasterjared
Learn from this picture:
Now, if you want to use Reference Finder, you need to know what fraction of the side you want.
First you calculate the total length of the side: 1+√2+4+4+1+√2=
10+2√2.
Then you find a point along the length. I would choose 2√2 or maybe 2*2√2=4√2 of the way down. In RefFinder this would be (10+2√2-4√2)=10-2√2, since the bottom left corner is (0,0)
So the points I would search for might be either
( [2√2]/[10+2√2] , 1 ) or
( 0 , [10-2√2]/[10+2√2] )
Also, while not totally accurate, here's a fairly close approximation for one of the points at the top:
EDIT: Since I'm a math major, I can't add. 4+4+1+1=10, not 8.
Posted: May 31st, 2009, 1:47 pm
by Cephalopod
Oh I see now. Thanks, that was very helpful.
Thankyou everyone.
Are the lengths always proportional to a 45 degree right angle triangle?
Posted: June 2nd, 2009, 5:52 am
by origamimasterjared
All right, I did a little more work on it, and managed to guess this:
