ReferenceFinder Tips and Tricks

[ftangdude55]

I got an answer of .7974,

Same for me.

[origamimasterjared]

Also, you can use Google as a basic scientific calculator. But instead of inputting that it's a 90 degree angle, use pi/2 radians (π/2):

tan(3/7*pi/2)=0.797473389

You don't need to understand that. Just know that π radians is equivalent to 180˚, so π/2=90˚.

[ftangdude55]

You know, I hope that, one day, I will completely understand what you are talking about, Jared (with the math and such).

[HankSimon]

You will understand if you take Trigonometry in High School. And, you may understand even better, if you take high math in college.

But right now, you may find that Origami helps a bit with geometry...

- Hank Simon

[WhisperPuffin]

ftangdude55: hi five I'm in grade 7 as well. Just listen to origamimasterjared, he'll know better than me!
Also, use the .7974 instead of a.

[Froy]

What I must do to calculate points wich references contains square roots of any number:

Example:

1+√2

I know this may look stupid but I'm not very familiar with matematics.

[origami_8]

I would just calculate it roughly 1+√2 = 2.414

[origamimasterjared]

Reference Finder can handle square roots. Just type in sqrt(2) for √2.

Remember, Reference Finder works on a 1 x 1 grid. This means that if, say, you have the top side of the square proportioned as 1+√2 : 1 the whole thing is 1+√2+1 = 2+√2. What you want to find is the point where the left side has 1+√2 and the other side.



Now, you want to describe the distance from the left corner to that point as a fraction of the side. In this case it would be (1+√2) / (2+√2).

The point you are looking for is:

• x1 = (1+sqrt(2))/(2+sqrt(2))
  y1 = 1