Reference Help
Forum rules
READ: The Origami Forum Rules & Regulations
READ: The Origami Forum Rules & Regulations

 Moderator
 Posts: 2335
 Joined: December 25th, 2011, 7:15 pm
 Location: Inside my twisted mind....
Re: Reference Help
Forgive the doublepost, but I've run into some trouble regarding the reference points for a model I've been working on.
The reference is (4+(2sqrt2)) : (7+(2sqrt2)). I'm going to use the midpoint of the edge as another reference point, so the equivalent proportion in each quadrant would be (from the corner) (4+(2sqrt2)) : 3. The first part is easy to find since it's essentially a Fish Base, but for some reason I'm having trouble constructing (7+(2sqrt2)).
An alternate proportion that would be of equal help is (3+(2sqrt2)) : 4. It, too, should be easier than I'm finding it to be.
Any help will be greatly appreciated.
The reference is (4+(2sqrt2)) : (7+(2sqrt2)). I'm going to use the midpoint of the edge as another reference point, so the equivalent proportion in each quadrant would be (from the corner) (4+(2sqrt2)) : 3. The first part is easy to find since it's essentially a Fish Base, but for some reason I'm having trouble constructing (7+(2sqrt2)).
An alternate proportion that would be of equal help is (3+(2sqrt2)) : 4. It, too, should be easier than I'm finding it to be.
Any help will be greatly appreciated.
Re: Reference Help
Hi guys. What references can I use to crease the following marks in my paper?
The rest of my model is very simple to fold so I do hope that this part doesn't get to complicated .
Thanks in advance!
The rest of my model is very simple to fold so I do hope that this part doesn't get to complicated .
Thanks in advance!
Last edited by Gerardo on April 6th, 2018, 1:39 am, edited 1 time in total.
Re: Reference Help
Theoretically you can use every method that gives you fifths.
http://www.origami.gr.jp/Archives/Peopl ... dexe.html
http://www.origami.at/diagrams/Fifths.pdf
http://www.origami.gr.jp/Archives/Peopl ... dexe.html
http://www.origami.at/diagrams/Fifths.pdf
Re: Reference Help
I like to use dichotomy to crease in 5ths (that's what is explained in the second link from origami_8 post).
The advantage is that you don't have unwanted creases (apart on an edge  but with a bit of practice, you can fold in 5ths quite exactly on your first iteration).
The advantage is that you don't have unwanted creases (apart on an edge  but with a bit of practice, you can fold in 5ths quite exactly on your first iteration).
Re: Reference Help
Thanks guys. I checked out the links you sent me origami_8. The tenth I need is regarding the diagonal middle of the paper. I think the method in the second weppage, the diagrams made by you Anna, is doable making the pinch folds over the diagonal middle instead of the border of the paper. I'm gonna try it out later today.
I was hoping there were other methods precisely because I'm looking for the tenth regarding the diagonal middle instead of the horizontal or vertical. What do you guys think?
I was hoping there were other methods precisely because I'm looking for the tenth regarding the diagonal middle instead of the horizontal or vertical. What do you guys think?
Re: Reference Help
Re: Reference Help
Ok, my mind was blown! I should've known that but I didn't . Thanks origami_8, this will be very useful for future models .
Also, I tried your method in the diagonal middle line and it worked perfectly .
Also, I tried your method in the diagonal middle line and it worked perfectly .

 Moderator
 Posts: 2335
 Joined: December 25th, 2011, 7:15 pm
 Location: Inside my twisted mind....
Re: Reference Help
Any ideas for how to achieve ((3sqrt2)+4) : 4 : 2 (from the corner) in one quadrant of the paper? I've tried everything I know, and nothing's given me the desired proportion.
It's for what I hope will be a final version of my Tiger model.
Thanks in advance.
It's for what I hope will be a final version of my Tiger model.
Thanks in advance.
Re: Reference Help
You're welcome!Gerardo wrote:Thanks origami_8

 Moderator
 Posts: 2335
 Joined: December 25th, 2011, 7:15 pm
 Location: Inside my twisted mind....
Re: Reference Help
Never mindI figured it out:Baltorigamist wrote:Any ideas for how to achieve ((3sqrt2)+4) : 4 : 2 (from the corner) in one quadrant of the paper?
(The blue lines mark the desired proportions, for anyone interested.)
https://s15i.imgup.net/Referencepa2ae.png
Re: Reference Help
This thread has been pretty inactive for a while but here goes.
The reference point I am trying to find is 1:1+2sqrt(64sqrt(2))+sqrt2.... Havent been able to quite understand some previous explanations, as images have since died.
Any help would be appreciated!
The reference point I am trying to find is 1:1+2sqrt(64sqrt(2))+sqrt2.... Havent been able to quite understand some previous explanations, as images have since died.
Any help would be appreciated!

 Moderator
 Posts: 2335
 Joined: December 25th, 2011, 7:15 pm
 Location: Inside my twisted mind....
Re: Reference Help
For irrational reference points of the form a+b(sqrt2), Satoshi Kamiya has a generator here. Tankoda, you might be able to convert your needed reference and use that.
Failing that, is there a desired split of the latter part of your reference point?
Failing that, is there a desired split of the latter part of your reference point?
Re: Reference Help
Thanks for the link, that looks helpful. I don't think my ratio can be simplified though...
What do you mean by a desired split?
What do you mean by a desired split?

 Moderator
 Posts: 2335
 Joined: December 25th, 2011, 7:15 pm
 Location: Inside my twisted mind....
Re: Reference Help
After crunching the numbers a little, I managed to simplify it down to 1 : (5sqrt2).
This translates to 1/(6sqrt2), which I put into Kamiya’s calculator as (6) + ((1)sqrt2). It gave a fairly easy solution, but I can’t link to it due to the limits of his site.
See if you get the same decimal as I did: 0.21806.
This translates to 1/(6sqrt2), which I put into Kamiya’s calculator as (6) + ((1)sqrt2). It gave a fairly easy solution, but I can’t link to it due to the limits of his site.
See if you get the same decimal as I did: 0.21806.
Re: Reference Help
The decimal representation I have is 0.278879...